31. How many times will the following code print the "warning" message?
count = 1
while count < 5:
print("warning")
count = count + 1
- 5
- 1
- 4
- 0
32. You are implementing security measures on a server. If a user has more than 3 failed login attempts, the program should print "locked out". The number of failed login attempts is stored in a variable called failed_attempts. Which conditional statement has the correct syntax needed to do this?
if failed_attempts >= 3
print(“locked out”)
if failed_attempts <= 3:
print(“locked out”)
if failed_attempts > 3:
print(“locked out”)
if failed_attempts < 3
print(“locked out”)
33. You have written the following code:
if operating_system == "OS 3":
print("Updates needed")
You want to add to it so that it will print a "No updates needed" message whenever the value of operating_system is not "OS 3". Which lines of code have the correct syntax to do this?
else:
print(“No updates needed”)
else
print(“No updates needed”)
elif operating_system == “OS 3”:
print(“No updates needed”)
else operating_system != “OS 3”:
print(“No updates needed”)
34. In a cybersecurity setting, which of these tasks would it be common to apply Python to? Select all that apply.
- Automating several tasks from a playbook into one workstream
- Manually checking individual timestamps in a log
- Automating how a log is read when responding to an incident
- Reducing the effort needed to manage an access control list
35. What is the syntax problem in the following code?
if username == "aestrada":
print("username found")
- The first line should be indented one space, and the second line should be indented two spaces.
- The line with print(“username found”) is not indented.
- The line with if username == “aestrada”: is not indented.
- Both lines are not indented.
36. What are the variables in the following code? Select all that apply.
username = "kcarter"
attempts = 5
print(username)
print(attempts)
print("locked")
- “kcarter”
- attempts
- username
- “locked”
37. You want to check the string stored in an update_status variable. When it contains a value of "incomplete", you want to print a "schedule update" message. Right now, this conditional statement is not correct. What are the problems with this conditional statement? Select all that apply.
if update_status != "incomplete"
print("schedule update")
- A colon (:) is missing at the end of the conditional header.
- The operator should not be !=. It should be ==.
- There should be quotation marks around the variable update_status.
- The line with print(“schedule update”) should not be indented.
38. You want to print all even numbers between 0 and 10 (in other words, 0, 2, 4, 6, 8, and 10). What should your next line of code be?
count = 0
while count <= 10:
print(count)
- count = count + 1
- if count < 10:
- count = 1
- count = count + 2